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Answer by Francesco Minnocci for Strengthening Ax-Grothendieck

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A version of OP's claim (with an additional hypothesis) is mentioned in a footnote on the first page of

where he says that M. Raynaud proved the following:

If $V$ is an algebraic variety, $f: V\to V$ has finite fibers, and is an immersion on a dense open subset of $V$, then $f$ is an isomorphism.


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